Find the force of mutual gravity of two bodies with a mass of 200 kg, located at a distance of 200 m from each other?

Initial data: m1 (mass of the first body) = m2 (mass of the second body) = 200 kg, R (distance between the given bodies) = 200 m.

Constants: G (gravitational constant) = 6.67 * 10 ^ -11 m ^ 3 * kg ^ -1 * s ^ -2).

The force of mutual gravitation of two given bodies to each other can be calculated using the formula:

F = G * m1 * m2 / R ^ 2.

F = G * m1 ^ 2 / R ^ 2.

Let’s do the calculation:

F = 6.67 * 10 ^ -11 * 200 ^ 2/200 ^ 2 = 6.67 * 10 ^ -11 H = 66.7 * 10 ^ -12 H = 66.7 pN.

Answer: The force of mutual gravity of two given bodies is 66.7 pN.