Find the force of pressure of kerosene to the bottom if it is in a hollow cube with an edge of 20 cm.

a = 20 cm = 0.2 m.
ρ = 800 kg / m ^ 3.
g = 9.8 m / s ^ 2.
F -?
Kerosene presses on the bottom of the cube with gravity: F = m * g, where m is the mass of kerosene, g is the acceleration of gravity.
The mass of kerosene m is determined by the formula: m = ρ * V, where ρ is the density of kerosene, V is the volume of kerosene.
The volume of kerosene will be determined by the volume of the cube in which it is located: V = a ^ 3.
F = ρ * a ^ 3 * g.
F = 800 kg / m ^ 3 * (0.2 m) ^ 3 * 9.8 m / s ^ 2 = 62.72 N.
Answer: the pressure force of kerosene on the bottom is F = 62.72 N.