Find the force of water pressure on the window of a submarine with an area of 200 cm ^ 3 at a depth of 40 meters.

Water pressure is determined by the formula
p = qgh, where
q – ro, density
g – acceleration of gravity
h – depth
Moreover, p = F / S, where
p- pressure
F – strength
S-area
In this case:
F = qghS
F = 1000 * 9.8 * 40 * 200 * 10 ^ (- 4) = 7840 N
Answer: F = 7840 N



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