Find the frequency v of natural electrical oscillations in a circuit consisting of a coil with

Find the frequency v of natural electrical oscillations in a circuit consisting of a coil with an inductance of 3 MHz and a capacitor with a capacity of 3 mF.

The frequency of natural electrical vibrations in the circuit is calculated using the formula:
n = 1 / T = 1 / (2 * Π * sqrt (L * C)), where L is the inductance of the coil (L = 3 mH = 3 * 10 ^ -3 H), C is the capacitance of the capacitor (C = 3 mF = 3 * 10 ^ -3 F).
Let’s calculate the frequency of natural electrical oscillations in the circuit:
n = 1 / (2 * Π * sqrt (L * C)) = 1 / (2 * 3.14 * sqrt ((3 * 10 ^ -3) * 3 * 10 ^ -3)) = 1 / (2 * 3.14 * 0.003) = 53 Hz.
Answer: The frequency of natural electrical oscillations in the circuit is 53 Hz.