Find the height of a building whose shadow length is 27m, and the sun shadow of a person 1m60cm tall is 2m40cm.

Let us prove that triangle ACD is similar to triangle ABK.

Both triangles are straight, since CD and BK are perpendicular to AD, and the angle A is common for the triangles, then the triangles are similar in acute angle.

CD / BK = AD / AK.

CD / 1.6 = 27 / 2.4.

2.4 * CD = 27 * 1.6.

2.4 * CD = 43.2.

CD = 43.2 / 2.4 = 18 m.

Answer: The height of the building is 18 meters.



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