Find the height of a rectangular parallelepiped, the volume of which is 1.35 dm2, length 2.25 m and width 8 dm.

1) First, find the base of the rectangular parallelepiped. The base of the parallelepiped is a rectangle with sides of 2.25 m and 8 dm.

The area of the rectangle is:

S = 2.25 m * 8 dm = 2.25 * 10 dm * 8 dm = 22.5 * 8 dm ^ 2 = 180 dm ^ 2.

2) In order to find the height of a rectangular parallelepiped, you need to divide its volume by the area of the base. It is known that the volume is 1.35 dm ^ 3.

h = 1.35 dm ^ 3/180 dm ^ 2 = 1.35 / 180 dm = 0.0075 dm.

This means that the height of the rectangular parallelepiped is 0.0075 dm.

Answer: h = 0.0075 dm.



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