Find the height to which a coin thrown upwards at a speed of 50 m / s will rise in three seconds.

Data: V0 – initial speed of the thrown coin (V0 = 50 m / s); t is the considered flight time of the coin (t = 3 s).

Const: g – acceleration of gravity, coins (g ≈ 10 m / s2).

1) Duration of lifting the coin: t = (0 – V0) / (-a) = V0 / g = 50/10 = 5 s (after 3 seconds the coin will still continue its ascent).

2) Coin height: S = h = V0 * t – g * t ^ 2/2 = 50 * 3 – 10 * 3 ^ 2/2 = 105 m;

Answer: After 3 seconds, the thrown coin should be at a height of 105 m.



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