Find the hypotenuse and sharp corners of a right-angled triangle if its legs are 9 cm and 40 cm.

Let’s determine how long the hypotenuse will be in our triangle, when from the condition of the task we know that the length of one leg is 9 centimeters, while the length of the other is 40 centimeters:

√ (9 ^ 2 + 40 ^ 2) = √ (81 + 1600) = √1681 = 41.

Determine what the sine of the angle will be equal to, which lies opposite the side of 9 centimeters:

9: 41 ≈ 0.2195.

This corresponds to an angle of 12.68 °.

Let’s determine what the second angle will be equal to:

90 – 12.68 = 77.32.

Answer: The angles will be 12.68 ° and 77.32 °, hypotenuse = 41 cm.