Find the induction emf in a conductor with an active part length of 0.28 m, moving in a uniform magnetic

Find the induction emf in a conductor with an active part length of 0.28 m, moving in a uniform magnetic field with an induction of 12 mT at a speed of 8 m / s at an angle of 60 degrees to the magnetic induction vector.

L = 0.28 m.

B = 12 mT = 0.012 T.

V = 8 m / s.

∠β = 60 °.

EMF -?

According to Faraday’s law of electromagnetic induction, EMF is directly proportional to the rate of change of the magnetic flux ΔF: EMF = ΔF / t.

The magnetic flux Ф is determined by the formula: Ф = B * S * cosα, where B is the magnetic induction, S is the area of ​​the contour, ∠α is the angle between the perpendicular to the area S and the vector of magnetic induction B.

EMF = Δ (B * S * cosα) / t = B * cosα * ΔS / t.

ΔS is the change in the area that the conductor describes.

ΔS = L * Δd, where Δd is the distance the conductor moved.

∠α = 90 ° – ∠β = 90 ° – 60 ° = 30 °.

EMF = B * cosα * L * Δd / t = B * cosα * L * V.

Δd / t = V.

EMF = 0.012 T * cos30 ° * 0.28 m * 8 m / s = 0.02 V.

Answer: EMF = 0.02 V.