Find the inside corners of a triangle if one of them is 3 times the other, and the outside angle

Find the inside corners of a triangle if one of them is 3 times the other, and the outside angle at the third vertex is 100 degrees.

1. One of the inner angles of the triangle is x degrees.

2. Another x * 3 = 3x degrees.

3. Let’s define the third one.

180 – 100 = 80 °.

4. Let’s make an equation.

x + 3x + 80 = 180;

4x = 100;

x = 100/4 = 25;

x = 25;

5. One angle x = 25 °.

6. Let’s calculate the other.

x * 3 = 25 * 3 = 75 °.

Answer: 25 °, 75 °, 80 °.