Find the intersection point of the lines 3x + 4y + 7 = 0 and 3x-y-5 = 0.

univerkov | November 23, 2020 | education

3x + 4y + 7 = 0
3x-y-5 = 0
3x = -4y-7
3x = y + 5
-4y-7 = y + 5
-4y-y = 5 + 7
-5y = 12
y = – (12/5)
y = -2.4
3x = -2.4
x = (- 2.4) / 3
x = -0.8
The intersection point of the lines has coordinates x; y = (- 0.8; -2.4)

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