Find the intervals of increasing, decreasing and extrema of the function f (x) = x ^ 3-3x-1.

Find the derivative of the function and equate it to zero:

(f (x)) ‘= (x ^ 3 – 3x – 1)’ = 3 * x ^ 2 – 3.

3 * x ^ 2 – 3 = 0

x ^ 2 = 1

x1 = 1 x2 = -2.

Since the derivative is positive in the interval from minus infinity to -2 and from 1 to infinity, the function increases, in the interval] -2; 1 [negative – the function is decreasing.



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