Find the large diagonal of a rhombus if one of its diagonals is 2 times larger than the other, and the area is 200 cm.

As we know from the school geometry course, the area of such a geometric figure can be calculated by the formula:

1/2 * d1 * d2, where d1 and d2 are the lengths of the diagonals of the geometric figure.

Let the smaller of the diagonals be equal to the variable a.

Then the larger of the diagonals can be represented by 2a.

Since we know that the area is 200 cm2, then it is possible to write down the equation and find out the length of the large diagonal:

a * 2a * 1/2 = 200;

a ^ 2 = 200;

a1 = 10√2;

a2 = -10√2 (not suitable).

2 * 10√2 = 20√2.

Answer: 20√2 cm.