Find the largest negative root of the equation 2sin x = – √3
| September 7, 2021 | education
Let’s find the general solution of the trigonometric equation:
2sin x = -√3;
sin x = -√3 / 2;
x1 = (4π / 3 ± 2n * n);
x2 = (5π / 3 ± 2n * n), where n is any integer.
The largest negative root of the equation will be:
x = 5π / 3 – 2p;
x = – n / 3.
Answer: x = – n / 3.
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