Find the length of a circle inscribed in a rhombus with a side equal to 12 and an acute angle of 30 degrees.

Let’s build the height BH of the rhombus ABCD.

In a right-angled triangle ABH, by condition, the angle BАH = 30.

The BH leg lies opposite an angle of 30, then its length is equal to half the length of the AB hypotenuse.

BH = AB / 2 = 12/2 = 6 cm.

The diameter of the inscribed rhombus of the circle is equal to the length of the height of the rhombus, then R = BH / 2 = 6/2 = 3 cm.

Determine the length of the inscribed circle.

L = 2 * π * R = 6 * π see.

Answer: The length of the inscribed circle is 6 * π cm.



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