Find the length of a mathematical pendulum that makes 30 oscillations in 20 seconds.

t = 20 s.

N = 30.

g = 10 m / s2.

L -?

The period of oscillation of any pendulum T is the time of one complete oscillation. The oscillation period of the pendulum T is determined by the formula: T = t / N, where t is the time during which the pendulum performs N complete oscillations.

T = t / N.

The period of the mathematical pendulum T is expressed by another formula: T = 2 * п * √L / √g, where п is the number pi, which is 3.14, L is the length of the thread of the mathematical pendulum, g is the acceleration of gravity.

t / N = 2 * п * √L / √g.

√L = t * √g / N * 2 * P.

L = t ^ 2 * g / N ^ 2 * 4 * P ^ 2.

L = (20 s) ^ 2 * 10 m / s2 / (30) ^ 2 * 4 * (3.14) ^ 2 = 0.11 m.

Answer: the mathematical pendulum has a length L = 0.11 m.



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