Find the length of the midline of the trapezoid with bases 4 cm and 7 cm.

Given:
ABCE – trapezoid
AB and CE – lateral sides of the trapezoid,
ВС and АЕ – trapezoid bases,
BC = 4 centimeters,
AE = 7 centimeters,
OH – the middle line of the trapezoid.
Find the length of the midline, that is, OH -?
Solution:
Consider the trapezoid ABCE. The middle line of the trapezium is parallel to the bases and the wound is half-sum. Therefore, the length of OH = 1/2 * (BC + AE);
OH = 1/2 * (4 + 7);
OH = 1/2 * 11;
OH = (1 * 11) / 2;
OH = 11/2;
OH = 5 1/2;
OH = 5.5 centimeters.
Answer: 5.5 centimeters.