Find the length of the segment and the coordinates if A (-2; 6) B (4; 8).

Let’s denote l as the length of the segment. l = √ ((x2 – x1) ^ 2 + (y2 – y1) ^ 2) = √ ((4 + 2) ^ 2 + (8 – 6) ^ 2) = √ (6 ^ 2 + 2 ^ 2) = √ (36 + 4) = √ (40). sqrt (x) is the arithmetic square root of x. A segment cannot have coordinates, probably, it was about a directed segment – a vector. Vector AB has coordinates (4 + 2; 8 – 6) => AB (6; 2). Vector BA has coordinates (-2 – 4; 6 – 8) => BA (-6; -2).