Find the lower height of the triangle with sides equal to 24cm, 25cm, 7cm.

By Heron’s theorem, we determine the area of the triangle ABC.

The semi-perimeter of the triangle ABC is equal to: p = (AB + BC + AC) / 2 = (25 + 24 + 7) / 2 = 28 cm.

Then Sас = √28 * (28 – 25) * (28 – 24) * (28 – 7) = √7056 = 84 cm2.

The lesser height of a triangle is the height drawn to the larger side of the triangle. then the CH height is the smallest.

Savs = AB * CH / 2.

СН = 2 * Saс / AB = 2 * 84/25 = 6.72 cm.

Answer: The length of the smaller side of the triangle is 6.72 cm.



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