Find the Mass and Number of Molecules for 44.8 L of Carbon Dioxide

n = V / Vm = 44.8 / 22.4 = 2 mol.

N = n * Na = 2 * 6.02 * 10 ^ 23 = 12.04 * 10 ^ 23 molecules.

Let’s determine the mass of carbon dioxide.

M (CO2) = 44 g / mol.

m / M = V / Vm.

m = M * V / Vm = 44 * 44.8 / 22.4 = 44 * 2 = 88 yy

Therefore, the mass of carbon dioxide is 88 g.



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