Find the mass and volume of carbon dioxide if 5 kg of CaCO3 are decomposed

Let’s carry out the solution, compose the reaction equation:
CaCO3 = CaO + CO2 – decomposition reaction, calcium oxide and carbon dioxide are obtained;
Let’s make calculations using the formulas:
M (CaCO3) = 40 +12 + 16 * 3 = 100 g / mol;
M (CO2) = 12 + 16 * 2 = 44 g / mol;
Determine the amount of moles of calcium carbonate, if the mass is known:
Y (CaCO3) = m / M = 5000/100 = 50 mol;
Let’s make the proportion:
50 mol (CaCO3) – X mol (CO2);
-1 mol                    -1 mol from here, X mol (CO2) = 50 * 1/1 = 50 mol;
Let’s calculate the volume of CO2 using Avogadro’s law:
Y (CO2) = 50 * 22.4 = 1120 l;
Let’s determine the mass of CO2 by the formula:
m (CO2) = Y * M = 50 * 44 = 2200 g;
Answer: the volume of carbon monoxide is 1120 liters, the mass of carbon monoxide is 2200 g.