Find the mass and volume of carbon dioxide that is generated by burning 36g of carbon.

Let’s implement the solution:

We write data on the condition of the problem:
m = 36 g X g -? X l -?

С + О2 = СО2 + Q – combustion, carbon dioxide is released;

Calculations by formulas:
M (C) = 12 g / mol;

M (CO2) = 44 g / mol.

Let’s determine the amount of the original substance:
Y (C) = m / M = 36/12 = 3 mol;

Y (CO2) = 3 mol since the amount of substances is equal to 1 mol.

We find the mass, volume of the product:
m (CO2) = Y * M = 3 * 44 = 132 g

V (CO2) = 3 * 22.4 = 67.2 l

Answer: obtained carbon monoxide (4) weighing 132 g, volume 67.2 liters.