# Find the mass and volume of hydrogen obtained by the interaction of zinc with sulfuric acid, mass of zinc = 130g

Zinc reacts violently with sulfuric acid to release hydrogen gas. In this case, zinc sulfate (zinc sulfate) is synthesized. This reaction is described by the following equation:

Zn + H2SO4 = ZnSO4 + H2;

The metal reacts with acid in equivalent molar amounts. At the same time, the same amounts of zinc sulfate and hydrogen are synthesized.

Let’s calculate the available chemical amount of metallic zinc. To do this, divide the weight of pure metal by the weight of 1 mole of metallic zinc.

M Zn = 65 grams / mol; N Zn = 130/65 = 2 mol;

The same amount of hydrogen and zinc sulfate will be synthesized.

Let’s calculate the volume of the synthesized amount of hydrogen. To do this, multiply its amount by the volume of 1 mole of gas (22.4 liters).

N H2 = 2 mol; V H2 = 2 x 22.4 = 44.8 liters;

Let’s calculate the weight of the synthesized amount of hydrogen.

N H2 = 2 mol; M H2 = 2 grams / mol; m H2 = 2 x 2 = 4 grams;

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