Find the mass and volume of hydrogen released during the reaction of 980 g of 20 sulfuric acid and zinc solution.

1. We write down the equation of interaction of zinc with sulfuric acid:

Zn + H2SO4 = ZnSO4 + H2 ↑;

2.Calculate the mass of sulfuric acid:

m (H2SO4) = w (H2SO4) * m (solution);

m (H2SO4) = 0.2 * 980 = 196 g;

3. find the chemical amount of acid:

n (H2SO4) = m (H2SO4): M (H2SO4);

M (H2SO4) = 2 + 32 + 4 * 16 = 98 g / mol;

n (H2SO4) = 196: 98 = 2 mol;

4. Determine the amount, mass and volume of released hydrogen:

n (H2) = n (H2SO4) = 2 mol;

m (H2) = n (H2) * M (H2) = 2 * 2 = 4 g;

V (H2) = n (H2) * Vm = 2 * 22.4 = 44.8 dm3.

Answer: 4 g; 44.8 dm3.