Find the mass fraction of all elements in glucose.

1. Formula of glucose:

C6H12O6;

2. Mass fraction is as follows:

ω = Ar (substance) / M (solution), where Ar is the relative atomic mass, M is the molar mass.

For glucose: ω (substance) = (Ar (substance) * 6) / M (solution of C6H12O6) * 100%.

3. We substitute the corresponding values in the formulas for each substance:

ω (C) = 72/180 * 100% = 40%;

ω (H) = 12/180 * 100% = 6.67%;

ω (O) = 96/180 * 100% = 53.33%;

Answer: ω (C) = 40%, ω (H) = 6.67%, ω (O) = 53.33%.