# Find the mass of 1 cubic meter of the alloy if the ingot of this alloy, which has the shape

Find the mass of 1 cubic meter of the alloy if the ingot of this alloy, which has the shape of a rectangular parallelepiped with dimensions of 2.9 dm, 15 cm and 0.8 m, has a mass of 281.88 kg.

It is required to determine the density of the alloy d = M / V (the ratio of the mass of the alloy M to the volume occupied by the alloy V).
The mass of the alloy is known M = 281.88 kg.
Let’s find the volume V of the rectangular parallelepiped by the formula V = a * b * c, where a, b, c are the measurements of the rectangular parallelepiped.
We express 2.9 dm and 15 cm in meters: 2.9 dm = (2.9 / 10) m = 0.29 m, 15 cm = (15/100) m = 0.15 m.
We have: V = (0.29 m) * (0.15 m) * (0.8 m) = 0.0348 m3.
Hence, d = M / V = (281.88 kg) / (0.0348 m3) = 8100 kg / m3.
Answer: 8100 kg / m3.

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