Find the Mass of 5 Moles of Baking Soda (NaHCO3)

Given:
n (NaHCO3) = 5 mol

To find:
m (NaHCO3) -?

1) M (NaHCO3) = Mr (NaHCO3) = Ar (Na) * N (Na) + Ar (H) * N (H) + Ar (C) * N (C) + Ar (O) * N (O ) = 23 * 1 + 1 * 1 + 12 * 1 + 16 * 3 = 84 g / mol;
2) m (NaHCO3) = n (NaHCO3) * M (NaHCO3) = 5 * 84 = 420 g.

Answer: The mass of NaHCO3 is 420 g.



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