Find the mass of 6 mol of AgNo3
| April 27, 2021 | education
The amount of silver nitrate substance is equal to – 6 mol.
Determine the mass of the connection. To solve, you need to use the following formula.
n = m / M.
Where n is the amount of substance.
m is the mass of the substance.
M – called molar mass.
M (AgNO3) = 108 + 14 + 48 = 170 g / mol.
m = n * M.
m = 170 * 6 = 1020 g.
Answer: the mass of silver nitrate is 1020 g.
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