Find the mass of acetic acid obtained by the oxidation of ethanol weighing 250 g.

Find the amount of ethanal substance CH3COH.

M (CH3COH) = 44 g / mol.

n = m: M.

n = 250 g: 44 g / mol = 5.68 mol.

Let’s compose the reaction equation. Let’s find the quantitative ratios of substances.

CH3COH + [O] → CH3COOH

According to the reaction equation, there is 1 mol of acetic acid CH3COOH per 1 mol of ethanal CH3COH. Substances are in quantitative ratios 1: 1.

n (CH3COH) = n (CH3COOH) = 5.68 mol.

Let’s find the mass of CH3COOH.

m = n × M,

M (CH3COOH) = 60 g / mol.

m = 5.68 mol × 60 g / mol = 340.8 g.

Answer: 340.8 g.