Find the mass of barium sulfate, which is formed by the interaction of a 24%

Find the mass of barium sulfate, which is formed by the interaction of a 24% solution of sulfuric acid weighing 190 grams with barium bromide.

Given:
ω (H2SO4) = 24%
m solution (H2SO4) = 190 g

To find:
m (BaSO4) -?

1) H2SO4 + BaBr2 => BaSO4 + 2HBr;
2) m (H2SO4) = ω * m solution / 100% = 24% * 190/100% = 45.6 g;
3) n (H2SO4) = m / M = 45.6 / 98 = 0.5 mol;
4) n (BaSO4) = n (H2SO4) = 0.5 mol;
5) m (BaSO4) = n * M = 0.5 * 233 = 117 g.

Answer: The mass of BaSO4 is 117 g.