Find the mass of benzene obtained from acetylene with a volume of 11.2 liters

Find the mass of benzene obtained from acetylene with a volume of 11.2 liters, if the benzene yield is 80% of the theoretical value.

1. Let’s write down the reaction equation:

3C2H2 = C6H6.

2. Find the amount of acetylene (Vm – molar volume, constant equal to 22.4 l / mol):

n (C2H2) = V (C2H2) / Vm = 11.2 L / 22.4 L / mol = 0.5 mol.

3. According to the reaction equation, we find the theoretical amount of benzene, and at the end its mass:

ntheor (C6H6) = n (C2H2) / 3 = 0.5 mol / 3 = 0.17 mol.

nprak (C6H6) = ntheor (C6H6) * η (C6H6) / 100% = 0.17 mol * 80% / 100% = 0.13 mol.

m (C6H6) = nprak (C6H6) * M (C6H6) = 0.13 mol * 78 g / mol = 10.4 g.

Answer: m (C6H6) = 10.4 g.