Find the mass of C2H5OH obtained from 44.8 liters of ethylene if the mass fraction of the alcohol yield is 80%.

univerkov | December 3, 2020 | education

C2H4 + H2O = C2H5OH
n (C2H4) = V \ Vm = 44.8 \ 22.4 = 2 mol
for ur-th p-and n (C2H4) = n (C2H5OH) = 2 mol
m theor (C2H5OH) = n * M = 2 * 46 = 92 g
output = m (practice) \ m (theory)
m (practical) = 0.8 * 92 = 73.6 g

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