Find the mass of calcium oxide formed during the decomposition of 250g. calcium carbonate

univerkov | August 10, 2021 | education

Find the mass of calcium oxide formed during the decomposition of 250g. calcium carbonate, the proportion of impurities in calcium carbonate is 15%.

CaCO3 = CaO + CO2

Reacted carbonate mass = (250 * 15) / 100 = 37.5g

M (CaCO3) = 40 + 12 + 16 * 3 = 100g / mol

Moles CaCO3 = 37.5g / 100g / mol = 0.375mol

Moles CaO = 0.375 mol

M (CaO) = 40 + 16 = 46g / mol

Mass CaO = 0.375 mol * 46 g / mol = 17.25 g

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