Find the mass of calcium oxide (g) and the volume of carbon dioxide (l) at normal conditions

Find the mass of calcium oxide (g) and the volume of carbon dioxide (l) at normal conditions, formed during the decomposition of 30 g of calcium carbonate. Give a solution. The mass of calcium oxide (g) and the volume of carbon dioxide (l) are respectively equal to

The thermal decomposition reaction of calcium carbonate is described by the following chemical reaction equation:

CaCO3 = CaO + CO2 ↑;

Let’s calculate the chemical amount of calcium carbonate (limestone). To do this, we divide its weight by the mass of 1 mole of the substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 30/100 = 0.3 mol;

The same molar amount of calcium oxide and carbon dioxide will theoretically be synthesized.

To find its volume, you need to multiply the amount of substance by the volume of 1 mole of gas (which is 22.4 liters).

V CO2 = 0.3 x 22.4 = 6.72 liters;

Let’s calculate the weight of calcium oxide. To do this, we multiply the amount of the substance by the weight of 1 mole of the substance.

M CaO = 40 + 16 = 56 grams / mol;

m CaO = 56 x 0.3 = 16.8 grams;