Find the mass of carbon dioxide obtained during the combustion of 10 g of C6H6

1. Let’s write down the reaction equation:

2С6H6 + 15O2 = 12CO2 + 6H2O.

2. Find the amount of benzene:

n (C6H6) = m (C6H6) / M (C6H6) = 10 g / 78 g / mol = 0.128 mol.

3. According to the reaction equation, we find the amount of carbon dioxide released, and then its mass:

12n (CO2) = 2n (C6H6).

n (CO2) = 2n (C6H6) / 12 = 2 * 0.128 mol / 12 = 0.021 mol.

m (CO2) = n (CO2) * M (CO2) = 0.021 mol * 44 g / mol = 0.94 g.

Answer: m (CO2) = 0.94 g.



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