Find the mass of carbon dioxide that is formed during the combustion of 40 g of butane.

Let’s compose the equation for the combustion reaction of butane:
2C4H10 + 13O2 = 8CO2 + 10H2O
Let’s calculate the amount of butane substance:
n (C4H10) = 40 g / 58 g / mol = 0.69 mol
M (C4H10) = 48 + 10 = 58 g / mol
Using the equation, we determine the amount of substance CO2:
n (CO2) = 4n (C4H10) = 4 * 0.69 = 2.76 mol
Let’s calculate the mass of CO2:
m (CO2) = 2.76 mol * 44 g / mol = 121.44 g