Find the mass of coal that is needed to produce 224 liters of carbon dioxide.

1. Let’s write the reaction equation:

C + O2 = CO2.

2. Find the amount of carbon dioxide (Vm – molar volume, constant equal to 22.4 l / mol)

n (CO2) = V (CO2) / Vm = 224 l / 22.4 l / mol = 10 mol.

3. According to the reaction equation, we find the amount, and then the mass of coal:

n (C) = n (CO2) = 10 mol.

m (C) = n (C) * M (C) = 10 mol * 12 g / mol = 120 g.

Answer: m (C) = 120 g.



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