Find the mass of copper that can be obtained from 156 g of CuO by reduction of H2.

According to the condition of the problem, we compose the reaction equation:
CuO + H2 = Cu + H2O – redox reaction, copper is released;
M (CuO) = 63.5 + 16 = 79.5 g / mol;
M (Cu) = 63.5 g / mol;
Let us calculate the amount of moles of copper oxide if the mass is known:
Y (CuO) = m / M = 156 / 79.5 = 1.96 mol;
Let’s make the proportion:
1.96 mol (CuO) – X mol (Cu);
-1 mol -1 mol hence, X mol (Cu) = 1.96 * 1/1 = 1.96 mol;
We find the mass of copper by the formula:
m (Cu) = Y * M = 1.96 * 63.5 = 124.46 g.
Answer: during the reaction, copper was obtained with a mass of 124.46 g.