Find the mass of ethanol that has undergone a dehydration reaction if 67.2 liters of ethylene are formed as a result.

Given:
V (C2H4) = 67.2 l

To find:
m (C2H5OH) -?

Decision:
1) C2H5OH = (H2SO4, 180C) => C2H4 + H2O;
2) n (C2H4) = V (C2H4) / Vm = 67.2 / 22.4 = 3 mol;
3) n (C2H5OH) = n (C2H4) = 3 mol;
4) m (C2H5OH) = n (C2H5OH) * M (C2H5OH) = 3 * 46 = 138 g.

Answer: The mass of C2H5OH is 138 g.



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