Find the mass of ethyl alcohol that can be obtained in the hydration reaction of 67.2 liters of ethylene.

| July 20, 2021 | education

Find the mass of ethyl alcohol that can be obtained in the hydration reaction of 67.2 liters of ethylene. The proportion of the yield of alcohol is 60% of the theoretically possible.

Let us write the equation for the reaction of obtaining ethanol:
C2H4 + H2O = C2H5OH.
Let’s find the number of moles of ethylene:
n (C2H4) = V / Vm = 67.2 / 22.4 = 3 mol.
Vm is a constant value that shows that 1 mole of any gas under normal conditions takes a volume of 22.4 liters.
It can be seen from the equation that the amount of moles of the starting material and the reaction product are equal.
n (C2H4) = n (C2H5OH).
Let’s find the theoretical mass of ethanol:
m (C2H5OH) = n * Mr = 3 * 46 = 138 g.
Accordingly, the practical mass will be equal to:
m (C2H5OH) = m * W / 100% = 138 * 60/100 = 82.8 g.



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