Find the mass of H2SO4 that was used to obtain HCl from 1.3 g of table salt containing 78% NaCl

m ‘(NaCl) = 1.3 gram
ω (NaCl) = 78% = 0.78
To find:
m (H2SO4) -?
m (NaCl) = m ‘(NaCl) * ω (NaCl) = 1.3 grams * 0.78 = 1.014 grams
M (NaCl) = 58.5 gram / mol
M (H2SO4) = 98 grams / mol
1.014 grams
2NaCl + H2SO4 = Na2SO4 + 2HCl
2 mol 1 mol
117 grams 98 grams
x = m (H2SO4) = 0.849 gram
Answer: 0.849 grams of sulfuric acid



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