Find the mass of hydrochloric acid to neutralize 8.7 g of sodium hydroxide

Find the amount of NaOH.

M (NaOH) = 40 g / mol.

n = m: M.

n = 8.7 g: 40 g / mol = 0.217 mol.

Let’s compose the reaction equation. Let’s find the quantitative ratios of substances.

NaOH + HCl = NaCl + H2O.

According to the reaction equation, 1 mol of NaOH accounts for 1 mol of HCl. Substances are in quantitative ratios 1: 1.

n (NaOH) = n (HCl) = 0.217 mol.

Let’s find the mass of НCl.

m = n × M,

M (HCl) = 36.5 g / mol.

m = 0.217 mol × 36.5 g / mol = 7.92 g.

Answer: 7.92 g.



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