Find the mass of hydrogen that is formed by the interaction of 66 g of zinc containing 1%

Find the mass of hydrogen that is formed by the interaction of 66 g of zinc containing 1% impurities with hydrochloric acid.

The reaction of zinc with hydrochloric acid is described by the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

Determine the mass of zinc:

m Zn = 60 x 0.99 = 59.4 grams;

Let’s determine the amount of zinc substance:

N Zn = 59.4 / 65 = 0.9138 mol;

The same amount of hydrogen will be produced. Let’s find its volume and mass:

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

V H2 = 0.9138 x 22.4 = 20.47 liters;

M H2O = 1 + 1 = 2 grams / mol;

m H2O = 2 x 0.9138 = 1.8276 grams;