Find the mass of hydrogen that was released during the interaction of magnesium 50 grams and hydrochloric acid?

univerkov | May 27, 2021 | education

1. Let’s write down the reaction equation:

Mg + 2HCl = MgCl2 + H2.

2. Find the amount of reacted magnesium:

n (Mg) = m (Mg) / M (Mg) = 50 g / 24 g / mol = 2.08 mol.

3. According to the reaction equation, we find the amount and then the mass of the released hydrogen:

n (H2) = n (Mg) = 2.08 mol.

m (H2) = n (H2) * M (H2) = 2.08 mol * 2 g / mol = 4.16 g.

Answer: m (H2) = 4.16 g.

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