Find the mass of iron hydroxide (lll) obtained by oxidation of 8 mol of iron hydroxide (ll),
October 9, 2021 | education
| Find the mass of iron hydroxide (lll) obtained by oxidation of 8 mol of iron hydroxide (ll), if the yield of iron hydroxide (lll) is 90%
To solve the problem, we compose the equation of the process:
4Fe (OH) 2 + O2 + 2H2O = 4Fe (OH) 3 – OBP, iron hydroxide (3) was obtained;
Calculations:
M Fe (OH) 3 = 106.8 g / mol.
3. Proportion:
8 mol Fe (OH) 2 – X mol Fe (OH) 3;
-4 mol -4 mol from here, X mol Fe (OH) 3 = 8 * 4/4 = 8 mol.
Find the mass of the product:
m Fe (OH) 3 = Y * M = 8 * 106.8 = 854.4 g (theoretical weight);
m Fe (OH) 3 = 0.90 * 854.4 = 768.96 g (practical weight).
Answer: Received iron (3) hydroxide weighing 768.96 g
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