Find the mass of iron hydroxide (lll) obtained by oxidation of 8 mol of iron hydroxide (ll), if the yield of iron hydroxide (lll) is 90%
To solve the problem, we compose the equation of the process:
4Fe (OH) 2 + O2 + 2H2O = 4Fe (OH) 3 – OBP, iron hydroxide (3) was obtained;
M Fe (OH) 3 = 106.8 g / mol.
8 mol Fe (OH) 2 – X mol Fe (OH) 3;
-4 mol -4 mol from here, X mol Fe (OH) 3 = 8 * 4/4 = 8 mol.
Find the mass of the product:
m Fe (OH) 3 = Y * M = 8 * 106.8 = 854.4 g (theoretical weight);
m Fe (OH) 3 = 0.90 * 854.4 = 768.96 g (practical weight).
Answer: Received iron (3) hydroxide weighing 768.96 g
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.