Find the mass of iron obtained by the interaction of 5.4 g of aluminum with iron oxide (3).

univerkov | June 16, 2021 | education

1. Let’s write down the reaction equation:

Fe2O3 + 2Al = 2Fe + Al2O3.

2. Find the amount of aluminum reacted:

n (Al) = m (Al) / M (Al) = 5.4 g / 27 g / mol = 0.2 mol.

3. According to the reaction equation, we find the amount, and then the mass of the formed iron:

n (Fe) = n (Al) = 0.2 mol.

m (Fe) = n (Fe) * M (Fe) = 0.2 mol * 56 g / mol = 11.2 g.

Answer: m (Fe) = 11.2 g.

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