Find the mass of magnesium oxide formed by the interaction of magnesium weighing 9.6 mg with oxygen.

Magnesium is oxidized very intensively by oxygen. The oxidation reaction is described by the following equation:

Mg + ½ O2 = MgO;

During oxidation, one oxygen atom is attached to the magnesium atom. In this case, one molecule of magnesium oxide is synthesized.

Let’s determine the molar amount of magnesium.

To do this, divide the available weight of magnesium by the weight of 1 mole of this substance.

M Mg = 24 grams / mol; N Mg = 9.6 / 1000/24 ​​= 0.0004 mol;

During the reaction, an equivalent amount of magnesium oxide will be synthesized.

Let’s find its weight.

To do this, multiply the amount of the substance by the weight of 1 mole of the substance.

M MgO = 24 + 16 = 40 grams / mol; m MgO = 0.0004 x 40 = 0.016 grams = 16 mg;