Find the mass of manganese oxide (4) that you need to take to obtain 14.2 g of chlorine from hydrochloric acid

Let’s implement the solution:

In accordance with the condition of the task, we write the data:
Xr -? m = 14.2 g

MnO2 + 4HCl = Cl2 + MnCl2 + 2H2O – OBP, chlorine is evolved;

Calculations:
M (MnO2) = 86.9 g / mol;

M (Cl2) = 71 g / mol;

Y (Cl2) = m / M = 14.2 / 71 = 0.2 mol;

Y (MnO2) = 0.2 mol since the amount of substances is 1 mol.

We find the mass of the original substance:
m (MnO2) = Y * M = 0.2 * 86.9 = 17.38 g

Answer: the mass of manganese oxide is 17.38 g