Find the mass of Na2S, which is formed by the interaction of Na weighing 9.2 g with sulfur

1. We write down the reaction equation for obtaining sodium sulfide:

2Na + S = Na2S;

2.Calculate the chemical amount of sodium:

n (Na) = m (Na): M (Na) = 9.2: 23 = 0.4 mol;

3.stoichiometric coefficients in front of sodium and its sulfide are related as 2: 1, we find the amount of Na2S:

n (Na2S) = n (Na): 2 = 0.4: 2 = 0.2 mol;

4.Calculate the mass of the obtained sulfide:

m (Na2S) = n (Na2S) * M (Na2S);

M (Na2S) = 2 * 23 + 32 = 78 g / mol;

m (Na2S) = 0.2 * 78 = 15.6 g.

Answer: 15.6 g.