Find the mass of NaNo3 required to prepare 300 ml of 0.2M solution.

Let’s find the required amount of the substance for the preparation of this solution.

To do this, multiply the volume of the solution and its molar concentration.

In order to prepare such a solution, it is necessary to weigh and dissolve 0.3 x 0.2 = 0.06 mol of salt in water.

Let’s find the required mass of salt.

To do this, multiply the molar weight of the salt by the chemical amount of the substance.

M NaNO3 = 23 + 14 + 16 x 3 = 85 grams / mol;

m NaNO3 = 0.06 x 85 = 5.1 grams;